-16x^2+44x+50=0

Solution for -16x^2+44x+50=0 equation:

-16x^2+44x+50=0

a = -16; b = 44; c = +50;
Δ = b2-4ac
Δ = 442-4·(-16)·50
Δ = 5136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5136}=\sqrt{16*321}=\sqrt{16}*\sqrt{321}=4\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{321}}{2*-16}=\frac{-44-4\sqrt{321}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{321}}{2*-16}=\frac{-44+4\sqrt{321}}{-32}
$